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x^2 - (x/2)^2 =
[#permalink]
14 Dec 2018, 10:14
3
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93% (00:34) correct
\(x^2 - (\frac{x}{2})^2 =\)
(A) \(x^2 - x\)
(B) \(\frac{x^2}{4}\)
(C) \(\frac{x^2}{2}\)
(D) \(\frac{3x^2}{4}\)
(E) \(\frac{3x^2}{2}\)
(A) \(x^2 - x\)
(B) \(\frac{x^2}{4}\)
(C) \(\frac{x^2}{2}\)
(D) \(\frac{3x^2}{4}\)
(E) \(\frac{3x^2}{2}\)
Re: x^2 - (x/2)^2 =
[#permalink]
14 Dec 2018, 10:23
1
Bookmarks
HKD1710 wrote:
\(x^2 - (\frac{x}{2})^2\) =
(A) \(x^2 - x\)
(B) \(\frac{x^2}{4}\)
(C) \(\frac{x^2}{2}\)
(D) \(\frac{3x^2}{4}\)
(E) \(\frac{3x^2}{2}\)
(A) \(x^2 - x\)
(B) \(\frac{x^2}{4}\)
(C) \(\frac{x^2}{2}\)
(D) \(\frac{3x^2}{4}\)
(E) \(\frac{3x^2}{2}\)
we can apply \(a^2 - b^2 = (a+b) (a-b)\)
\(x^2 - (x/2)^2\)
(x + x/2) ( x - x/2)
(\(\frac{2x + x}{2}\)) (\(\frac{2x - x}{2}\))
\(\frac{3x *x}{4}\)
\(\frac{3x^2}{4}\)
The best answer is D.
Re: x^2 - (x/2)^2 =
[#permalink]
22 Jun 2019, 04:05
KSBGC wrote:
HKD1710 wrote:
\(x^2 - (\frac{x}{2})^2\) =
(A) \(x^2 - x\)
(B) \(\frac{x^2}{4}\)
(C) \(\frac{x^2}{2}\)
(D) \(\frac{3x^2}{4}\)
(E) \(\frac{3x^2}{2}\)
(A) \(x^2 - x\)
(B) \(\frac{x^2}{4}\)
(C) \(\frac{x^2}{2}\)
(D) \(\frac{3x^2}{4}\)
(E) \(\frac{3x^2}{2}\)
we can apply \(a^2 - b^2 = (a+b) (a-b)\)
\(x^2 - (x/2)^2\)
(x + x/2) ( x - x/2)
(\(\frac{2x + x}{2}\)) (\(\frac{2x - x}{2}\))
\(\frac{3x *x}{4}\)
\(\frac{3x^2}{4}\)
The best answer is D.
Hey, is solving mathematically right too ?
As in
X^2 - (X/2)^2
X^2 - X^2/4
(4X^2- X^2)/4
3x^2/4..