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If p = 0.2 and n = 100, then (p(1-p)/n)^(1/2) =
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05 Dec 2018, 08:52
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89% (01:06) correct
If p = 0.2 and n = 100, then \(\sqrt{\frac{p(1-p)}{n}}\) =
(A) - \(\sqrt{0.002}\)
(B) \(\sqrt{0.0002}\) - 0.02
(C) 0
(D) 0.04
(E) 0.4
(A) - \(\sqrt{0.002}\)
(B) \(\sqrt{0.0002}\) - 0.02
(C) 0
(D) 0.04
(E) 0.4
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Joined: 12 Sep 2015
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Re: If p = 0.2 and n = 100, then (p(1-p)/n)^(1/2) =
[#permalink]
Updated on: 21 Sep 2021, 17:55
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HKD1710 wrote:
If p = 0.2 and n = 100, then \(\sqrt{\frac{p(1-p)}{n}}\) =
(A) - \(\sqrt{0.002}\)
(B) \(\sqrt{0.0002}\) - 0.02
(C) 0
(D) 0.04
(E) 0.4
(A) - \(\sqrt{0.002}\)
(B) \(\sqrt{0.0002}\) - 0.02
(C) 0
(D) 0.04
(E) 0.4
\(\sqrt{\frac{p(1-p)}{n}} = \sqrt{\frac{0.2(1-0.2)}{100}}\)
\(= \sqrt{\frac{0.2(0.8)}{100}}\)
\(= \sqrt{\frac{0.16}{100}}\)
\(= \sqrt{\frac{16}{10,000}}\)
\(= \frac{√16}{√10,000}\)
\(= \frac{4}{100}\)
\(= 0.04\)
Answer: D
Originally posted by BrentGMATPrepNow on 05 Dec 2018, 09:12.
Last edited by BrentGMATPrepNow on 21 Sep 2021, 17:55, edited 1 time in total.
Last edited by BrentGMATPrepNow on 21 Sep 2021, 17:55, edited 1 time in total.
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Re: If p = 0.2 and n = 100, then (p(1-p)/n)^(1/2) =
[#permalink]
05 Dec 2018, 10:03
P = 0.2
N = 100
=> \(\sqrt{\frac{0.2(1-0.2)}{100}}\)
=> \(\sqrt{\frac{0.20 * 0.80}{100}}\)
=> \(\sqrt{\frac{0.1600}{100}}\) (Multiply by 10000)
=>\(\sqrt{\frac{1600}{1000000}}\)
=>\(\sqrt{\frac{16}{10000}}\)
=>\(\frac{4}{100}\)
=>\(\frac{1}{25}\)
=>0.04
N = 100
=> \(\sqrt{\frac{0.2(1-0.2)}{100}}\)
=> \(\sqrt{\frac{0.20 * 0.80}{100}}\)
=> \(\sqrt{\frac{0.1600}{100}}\) (Multiply by 10000)
=>\(\sqrt{\frac{1600}{1000000}}\)
=>\(\sqrt{\frac{16}{10000}}\)
=>\(\frac{4}{100}\)
=>\(\frac{1}{25}\)
=>0.04