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Math Expert
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Re: In how many arrangements can a teacher seat 3 girls and 3 boys in a [#permalink]
Expert Reply
Assume that there are only 3 chairs for the boys to sit.
So they can be arranged in 3! Ways.

Now put 3 more chairs between 1st and 2nd boy, 2nd and 3rd boy ,and next to the 3rd boy.
So another 3! Ways..

Each positioning of boys will have 3! Ways of positioning girls
So total ways = 3!*3!=6*6=36

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Re: In how many arrangements can a teacher seat 3 girls and 3 boys in a [#permalink]
My 2 cents on this:

This question could easily be framed differently increasing the difficult, so be careful.

1st way --> whenever the word rearrangements/arrangements appear, I look at npr formulas. So, 3 boys have 3 seats available, hence 3! ways. Same for 3 Girls, 3 chairs, 3! ways. Total = 3! x 3! = 36 ways

2nd way: 3c1 x 3c1 x 2c1 x 2c1 x 1c1 x 1c1 (B,G,B,G,B) = 36 ways

Bunuel, what do you think of the 2nd way? Will it work in more complex questions?
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Re: In how many arrangements can a teacher seat 3 girls and 3 boys in a [#permalink]
­There are 3 girls and 3 boys and 6 seats, and two of the same gender can't sit together.

_ _ _ _ _ _
G B G B G B - Method 1
B G B G B G - Method 2

1 seat - 6 options
2 seat - 3 options ( B if G occupies 1 or vice versa) 
3 seat - 2 options ( B if G occupies 2 or vice versa)
4 seat - 2 options ( B if G occupies 3 or vice versa)
5 seat - 1 option   ( B if G occupies 4 or vice versa)
6 seat - 1 option   ( B if G occupies 5 or vice versa)

Total possible arrangements - 6*3*2*2*1*1 = 72 (D)

Answer - D
Re: In how many arrangements can a teacher seat 3 girls and 3 boys in a [#permalink]
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