area of a regular hexagon

thanks for the link.

A regular hexagon can be divided into 6 equilateral triangles of equal area, with all sides of respective triangles (except of course, the side that is a part of the hexagon), meeting at the center of hexagon.

1. If one side is known, you can calculate the area of one equilateral triangle by calculating its altitude first (the altitude of an equilateral triangle= \((sqrt3)\)/ 4) then calculating its area (\(\frac{1}{2}* base* altitude\)). Multiply this area by 6 (as there are 6 similar triangles of equal area) and you have the area for the hexagon.

2. Divide hexagon into 6 equilateral triangles. The altitude from the center to the side is equal to the altitude of each one of the equilateral triangle. If you know the altitude of an equilateral triangle, you can calculate its sides. So, the area of 1 equilateral will be \(\frac{1}{2}*altitude*base\). multiply the value by 6 and you're good