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A furniture store sells only two models or desks, model A and model B
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25 May 2017, 13:28
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A furniture store sells only two models or desks, model A and model B The selling price of model A is $120, which is 30 percent of the selling price of model B If the furniture store sells 2,000 desks, \(\frac{3}{4}\) of which are model B, what is the furniture store's total revenue from the sale of desks?
(A) $114,000
(B) $186,000
(C) $294,000
(D) $380,000
(E) $660,000
(A) $114,000
(B) $186,000
(C) $294,000
(D) $380,000
(E) $660,000
Re: A furniture store sells only two models or desks, model A and model B
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25 May 2017, 13:41
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carcass wrote:
A furniture store sells only two models or desks, model A and model B The selling price of model A is $120, which is 30 percent of the selling price of model B If the furniture store sells 2,000 desks, \(\frac{3}{4}\) of which are model B, what is the furniture store's total revenue from the sale of desks?
(A) $114,000
(B) $186,000
(C) $294,000
(D) $380,000
(E) $660,000
(A) $114,000
(B) $186,000
(C) $294,000
(D) $380,000
(E) $660,000
(the price of model B)*3/10 = $120;
(the price of model B) = $400.
Out of 2000 desks \(\frac{3}{4}*2000=1500\) were model B and the remaining 500 were model A.
Total revenue = 120*500 + 400*1500 = $660,000.
Answer: E.
A furniture store sells only two models or desks, model A and model B
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25 May 2017, 19:32
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Selling price of Model A= $120
Selling price of Model B= 120*\(\frac{100}{30}\)= $400
No of desks of Model B sold= \(\frac{3}{4}\)*2000= 1500
No of desks of Model A sold= 2000-1500= 500
Revenue from Model A= 120*500= $60,000
Revenue from Model B= 400*1500= $6,00,000
Total Revenue= $60,000+$6,00,000= $6,60,000
Answer: E.
Selling price of Model B= 120*\(\frac{100}{30}\)= $400
No of desks of Model B sold= \(\frac{3}{4}\)*2000= 1500
No of desks of Model A sold= 2000-1500= 500
Revenue from Model A= 120*500= $60,000
Revenue from Model B= 400*1500= $6,00,000
Total Revenue= $60,000+$6,00,000= $6,60,000
Answer: E.