Schachfreizeit wrote:
temp33 wrote:
IMO C
Average speed for the entire trip = 2uv/(u+v),
where u = speed of going
v = speed of returning
Thus, average speed = 2*40*30/(70) = 34.3 mi/h
Hence, C
what kind of formula is this?
Hi
Schachfreizeit,
Thanks for your query.
The formula you are asking about is the simplified version of the average speed formula for a round trip. Let me show you how!
Please go through the explanation below, where I used a hypothetical situation to derive the formula of the average speed you are confused about. I will only use the definition of average speed.
DERIVATION: Suppose the distance between two random points - point A and point B - is ‘d’ meters. A car moves from A to B at a speed of ‘u’ miles/hour and then returns from B to A at a speed of ‘v’ miles/hour. We need to find the average speed for this round trip by car A. Now, by the definition of average speed, we know that:
Average speed = \(\frac{Total distance}{Total time}\) …(I)
Let’s try to find the numerator and denominator separately, using information from our hypothetical situation.
- Total distance covered by the car = d (from A to B) + d (from B to A) = 2d …(II)
- Total time taken= Time taken from A to B + Time taken from B to A
= \(\frac{distance}{speed}\)(From A to B) + \(\frac{distance}{speed}\)(From B to A)
=\(\frac{d}{u}+\frac{d}{v}\) = \(\frac{(dv + du)}{uv}\) = \(\frac{d(v + u)}{uv}\) …(III)
So, using the values of total distance and total time from (II) and (III) into (I), we get
- Average speed = \(\frac{2d}{{d(u+v)/uv}}\)= \(\frac{2duv}{d(u+v)}\)=\(\frac{2uv}{(u+v)}\)
And see! This is the formula you were looking for.
APPLICATION OF THE FORMULA: Let me again show you how this formula can be directly used to solve our question:
Here, we have u = 30 miles per hour and v = 40 miles per hour. Using these values in the formula we derived, we get:
- Average speed = \(\frac{2(30)(40)}{(30+40)}\)= 34.28 miles per hour
TAKEAWAY: Whenever speed for
to journey and
back journey is given, where the distances in both legs of the journey are identical, we can directly use the following formula to find average speed.
- Average speed = \(\frac{2uv}{u+v}\), where u, v are the speeds of the “to” and “back” journeys, respectively.
Hope this helps!
Best,
Aditi Gupta
Quant Expert,
e-GMAT