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Re: A company will select 2 of the 6 candidates available to work in 2 dif [#permalink]
Can some explain the operations and notation here? I don’t know what the letter C means and I see it in all the explanations.

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Re: A company will select 2 of the 6 candidates available to work in 2 dif [#permalink]
VeritasKarishma wrote:
mangamma wrote:
A company will select 2 of the 6 candidates available to work in 2 different positions in Technology team and 3 of the 7 candidates to work in the same position in HR team. Find the number of ways in which company can fill the positions?


A. 57
B. 65
C. 128
D. 256
E. 1050


2 are to be selected out of 6 for 2 different positions hence it involves selection and arrangement on the two positions.
First position can be filled in 6 ways and second in 5 ways to give a total of 6*5= 30 ways

3 of the 7 candidates are to be selected for the same role e.g. HR manager. So here we only need to select 3 of 7 in 7C3 = 35 ways.

So the company can fill the positions in 30*35 = 1050 ways

For more, check: https://www.gmatclub.com/forum/veritas-prep-resource-links-no-longer-available-399979.html#/2011/1 ... inatorics/
https://www.gmatclub.com/forum/veritas-prep-resource-links-no-longer-available-399979.html#/2011/1 ... binations/



Hi VeritasKarishma

I have a doubt here. I think the two events are independent(selecting technology people and selecting HR people).

Technology team is different and we cannot put HR people in them.

Should not we add instead of multiplying.
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Re: A company will select 2 of the 6 candidates available to work in 2 dif [#permalink]
Why are we multiplying 30 and 35 here. Isn't it a mutually exclusive event? Someone explain please.

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Re: A company will select 2 of the 6 candidates available to work in 2 dif [#permalink]
Sujon2160 wrote:
Why are we multiplying 30 and 35 here. Isn't it a mutually exclusive event? Someone explain please.

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Hi Sujon2160! I'm not an expert, but will try to explain! Consider this: for every "combination" of people in Technology team, there are 35 possible combinations for HR team (since they are indeed independent). For the next combination in Technology team, the same 35 in HR team are possible. Hence, we could simply multiply 30 by 35 to get all possible combinations for both teams.

Hope it's clear

Best,
Andre
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Re: A company will select 2 of the 6 candidates available to work in 2 dif [#permalink]
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Re: A company will select 2 of the 6 candidates available to work in 2 dif [#permalink]
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