(Go: >> BACK << -|- >> HOME <<)

Last visit was: 18 Jun 2024, 15:51 It is currently 18 Jun 2024, 15:51
Close
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Close
Request Expert Reply
Confirm Cancel
SORT BY:
Date
Math Expert
Joined: 02 Sep 2009
Posts: 93736
Own Kudos [?]: 632853 [29]
Given Kudos: 82345
Send PM
Current Student
Joined: 16 Jan 2019
Posts: 623
Own Kudos [?]: 1464 [1]
Given Kudos: 142
Location: India
Concentration: General Management
GMAT 1: 740 Q50 V40
WE:Sales (Other)
Send PM
GMAT Club Legend
GMAT Club Legend
Joined: 08 Jul 2010
Status:GMAT/GRE Tutor l Admission Consultant l On-Demand Course creator
Posts: 6014
Own Kudos [?]: 13639 [3]
Given Kudos: 124
Location: India
GMAT: QUANT+DI EXPERT
Schools: IIM (A) ISB '24
GMAT 1: 750 Q51 V41
WE:Education (Education)
Send PM
Math Expert
Joined: 02 Sep 2009
Posts: 93736
Own Kudos [?]: 632853 [2]
Given Kudos: 82345
Send PM
Re: Three friends A, B and C decide to run around a circular track. They [#permalink]
1
Bookmarks
Expert Reply
GMATinsight wrote:
Bunuel wrote:
Three friends A, B and C decide to run around a circular track. They start at the same time, from the same point and run in the same direction. A is the quickest and when A finishes the first lap lap, C is as much behind B as B is behind A. When A completes 3 laps, C is at the exact same point on the circular track as B was when A finished the first lap. What is the ratio of the speeds of A, B and C?

A. 6 : 5 : 3
B. 5 : 4 : 2
C. 4 : 3 : 2
D. 5 : 4 : 3
E. 3 : 2 : 1



Are You Up For the Challenge: 700 Level Questions


Hi harleensingh
firas92

Let, Track length = 100 and B is x unit behind A when A finishes first track
A = 100
B = 100-x
C = 100-2x

When, A = 300
DIstance travelled by C = 100-x or 100+100-x

i.e. A/C = 100/(100-2x) = 300/(100-x) or 300/(200-x)

i.e. 3(100-2x) = 100-x or 3(100-2x) = 200-x

i.e. 300-6x = 100-x or 300-6x = 200-x

i.e. 5x = 200 and x = 40 or 5x = 100 and x = 20

i.e. A/C = 100/20 or 100/60

i.e. A/C = 5/1 or 5/3

Only Option D gives A/C = 5/3

Answer: Option D

Bunuel : OA mentioned seems INCORRECT. Please check

________________________
Edited. Thank you.
GMAT Club Legend
GMAT Club Legend
Joined: 08 Jul 2010
Status:GMAT/GRE Tutor l Admission Consultant l On-Demand Course creator
Posts: 6014
Own Kudos [?]: 13639 [1]
Given Kudos: 124
Location: India
GMAT: QUANT+DI EXPERT
Schools: IIM (A) ISB '24
GMAT 1: 750 Q51 V41
WE:Education (Education)
Send PM
Re: Three friends A, B and C decide to run around a circular track. They [#permalink]
1
Kudos
Expert Reply
Bunuel wrote:
Three friends A, B and C decide to run around a circular track. They start at the same time, from the same point and run in the same direction. A is the quickest and when A finishes the first lap lap, C is as much behind B as B is behind A. When A completes 3 laps, C is at the exact same point on the circular track as B was when A finished the first lap. What is the ratio of the speeds of A, B and C?

A. 6 : 5 : 3
B. 5 : 4 : 2
C. 4 : 3 : 2
D. 5 : 4 : 3
E. 3 : 2 : 1



Are You Up For the Challenge: 700 Level Questions


Bunuel I am sorry to bother you again but C option doesn't fit with question conditions while Option D fits

Suppose Track length is 4
As per option C
WHen A completes one LAP i.e. 4 unit distance then B is at 3 (at 3/4) the mark of track length and C is at 2

After 3 laps
A completes 12 units B completes 9 units and C travels 6 units

i.e. C is at the midpoint of the track i.e. C is not at mark where B was when A completed first lap
Math Expert
Joined: 02 Sep 2009
Posts: 93736
Own Kudos [?]: 632853 [0]
Given Kudos: 82345
Send PM
Re: Three friends A, B and C decide to run around a circular track. They [#permalink]
Expert Reply
GMATinsight wrote:
Bunuel I am sorry to bother you again but C option doesn't fit with question conditions while Option D fits

Suppose Track length is 4
As per option C
WHen A completes one LAP i.e. 4 unit distance then B is at 3 (at 3/4) the mark of track length and C is at 2

After 3 laps
A completes 12 units B completes 9 units and C travels 6 units

i.e. C is at the midpoint of the track i.e. C is not at mark where B was when A completed first lap


________________________
Edited. Thank you.
Current Student
Joined: 16 Jan 2019
Posts: 623
Own Kudos [?]: 1464 [0]
Given Kudos: 142
Location: India
Concentration: General Management
GMAT 1: 740 Q50 V40
WE:Sales (Other)
Send PM
Re: Three friends A, B and C decide to run around a circular track. They [#permalink]
At the end of A's 3rd lap, the distance between A and C must be

Track length + Distance between A and B at the end of 1st lap

If the track length is 500m and the speed ratio is 5:4:3

A's first lap, A:B:C=500:400:300
A's second lap, A:B:C=1000:800:600
A's third lap, A:B:C=1500:1200:900

So the distance between A and C at the end ofnA's third lap is 1500-900=600=500+100 (track length + Distance between A and B at the end of A's first lap)

This perfectly matches our requirement.

Answer is (D)

Posted from my mobile device
Manager
Manager
Joined: 01 Feb 2017
Posts: 242
Own Kudos [?]: 354 [1]
Given Kudos: 148
Send PM
Re: Three friends A, B and C decide to run around a circular track. They [#permalink]
1
Kudos
Let length of the track be 1
Speed of A, B and C = a, b, c respectively

Time instant 1:
Distance covered by A= 1
by B= 1-x
by C= 1-2x

Time ratio: A:B:C= 1/a : (1-x)/b : (1-2x)/c
Speed ratio: a:b:c = 1:1-x:1-2x

Time instant 2:
Distance covered by A= 3
by C= 2-x (cannot be 3-x as relative distance between A-C must increase)

Time ratio: A:C= 3/a : (2-x)/c
Speed ratio: a:c = 3:2-x

Therefore, a/c = 1/(1-2x) = 3/(2-x)
x= 1/5

So, a:b:c = 1: 4/5 : 3/5 = 5:4:3

Ans D
Intern
Intern
Joined: 12 Apr 2020
Posts: 3
Own Kudos [?]: 0 [0]
Given Kudos: 1
Send PM
Re: Three friends A, B and C decide to run around a circular track. They [#permalink]
The question states "When A completes 3 laps, C is at the exact same point on the circular track as B was when A finished the first lap."
So why do we need to measure distances?
Looking at firas92 explanation, C's position when A finished the third lap is in 900M point/mark and why is it not simply B's point/mark when A finished its first lap?

Slightly copying firas92's diagram here - isnt the question saying
A's 1st Lap - A:500M point === B:400M point === C:300M point
A's 2nd Lap - A:xxx === B:xxx === C:xxx
A's 3rd Lap - A:xxx === B: xxx === C: 400M Point

?

Cheers
Current Student
Joined: 16 Jan 2019
Posts: 623
Own Kudos [?]: 1464 [0]
Given Kudos: 142
Location: India
Concentration: General Management
GMAT 1: 740 Q50 V40
WE:Sales (Other)
Send PM
Re: Three friends A, B and C decide to run around a circular track. They [#permalink]
gorbyrodo wrote:
The question states "When A completes 3 laps, C is at the exact same point on the circular track as B was when A finished the first lap."
So why do we need to measure distances?
Looking at firas92 explanation, C's position when A finished the third lap is in 900M point/mark and why is it not simply B's point/mark when A finished its first lap?

Slightly copying firas92's diagram here - isnt the question saying
A's 1st Lap - A:500M point === B:400M point === C:300M point
A's 2nd Lap - A:xxx === B:xxx === C:xxx
A's 3rd Lap - A:xxx === B: xxx === C: 400M Point

?

Cheers


gorbyrodo

That would mean that C is not maintaining constant speed and so the ratio between the speeds of A and C will not be the same throughout the race.

Hope its clear :)

Posted from my mobile device
Intern
Intern
Joined: 12 Apr 2020
Posts: 3
Own Kudos [?]: 0 [0]
Given Kudos: 1
Send PM
Re: Three friends A, B and C decide to run around a circular track. They [#permalink]
A's 1st Lap - A:500M point === B:400M point === C:300M point
A's 2nd Lap - A:xxx === B:xxx === C:xxx
A's 3rd Lap - A:xxx === B: xxx === C: 400M Point

?

Cheers[/quote]


That would mean that C is not maintaining constant speed and so the ratio between the speeds of A and C will not be the same throughout the race.

Hope its clear :)

Posted from my mobile device[/quote]

HI firas92. sorry for the late reply mate.

Thats the thing though, with the way the question is laid out it doesnt seem that constant speed is not maintained by C.
If we were to assume that C's speed is maintained, then wouldnt the illustration looks like this?

A's 1st Lap - A:500M point === B:300M point === C:100M point
A's 2nd Lap - A:xxx === B:xxx === C:xxx
A's 3rd Lap - A:xxx === B: xxx === C:300M Point

C is maintaining 100M throughout A's run. Thus the ratio would be 5:3:1
Current Student
Joined: 16 Jan 2019
Posts: 623
Own Kudos [?]: 1464 [0]
Given Kudos: 142
Location: India
Concentration: General Management
GMAT 1: 740 Q50 V40
WE:Sales (Other)
Send PM
Re: Three friends A, B and C decide to run around a circular track. They [#permalink]
gorbyrodo wrote:
A's 1st Lap - A:500M point === B:400M point === C:300M point
A's 2nd Lap - A:xxx === B:xxx === C:xxx
A's 3rd Lap - A:xxx === B: xxx === C: 400M Point

?

Cheers



That would mean that C is not maintaining constant speed and so the ratio between the speeds of A and C will not be the same throughout the race.

Hope its clear :)

Posted from my mobile device[/quote]

HI firas92. sorry for the late reply mate.

Thats the thing though, with the way the question is laid out it doesnt seem that constant speed is not maintained by C.
If we were to assume that C's speed is maintained, then wouldnt the illustration looks like this?

A's 1st Lap - A:500M point === B:300M point === C:100M point
A's 2nd Lap - A:xxx === B:xxx === C:xxx
A's 3rd Lap - A:xxx === B: xxx === C:300M Point

C is maintaining 100M throughout A's run. Thus the ratio would be 5:3:1[/quote]

I get your point now. 5:3:1 could be an answer as explained by GMATinsight above.

I just worked with the given options and D was the only one that fit so I didn't consider 5:3:1
Current Student
Joined: 03 Dec 2020
Posts: 60
Own Kudos [?]: 98 [1]
Given Kudos: 217
Location: India
Debrief: https://gmatclub.com/forum/740-v40-q50-second-attempt-self-preparation-375379.html
Concentration: Technology, Strategy
GMAT 1: 720 Q49 V39
GMAT 2: 740 Q50 V40
WE:Engineering (Computer Hardware)
Send PM
Re: Three friends A, B and C decide to run around a circular track. They [#permalink]
1
Kudos
GMATinsight wrote:
Bunuel wrote:
Three friends A, B and C decide to run around a circular track. They start at the same time, from the same point and run in the same direction. A is the quickest and when A finishes the first lap lap, C is as much behind B as B is behind A. When A completes 3 laps, C is at the exact same point on the circular track as B was when A finished the first lap. What is the ratio of the speeds of A, B and C?

A. 6 : 5 : 3
B. 5 : 4 : 2
C. 4 : 3 : 2
D. 5 : 4 : 3
E. 3 : 2 : 1



Are You Up For the Challenge: 700 Level Questions


Hi harleensingh
firas92

Let, Track length = 100 and B is x unit behind A when A finishes first track
A = 100
B = 100-x
C = 100-2x

When, A = 300
DIstance travelled by C = 100-x or 100+100-x

i.e. A/C = 100/(100-2x) = 300/(100-x) or 300/(200-x)

i.e. 3(100-2x) = 100-x or 3(100-2x) = 200-x

i.e. 300-6x = 100-x or 300-6x = 200-x

i.e. 5x = 200 and x = 40 or 5x = 100 and x = 20

i.e. A/C = 100/20 or 100/60

i.e. A/C = 5/1 or 5/3

Only Option D gives A/C = 5/3

Answer: Option D

Bunuel : OA mentioned seems INCORRECT. Please check or post OE


Bunuel chetan2u IanStewart VeritasKarishma GMATinsight
Is there any specific reason why A/C = 5/1 is rejected, and 5/3 is the OA
I feel both the options are viable.
Please help.

Also, in the real GMAT exam, is it possible to get questions which have multiple answers as per multiple cases, but OA is specific to only one case ?

Thanks!
GMAT Tutor
Joined: 24 Jun 2008
Posts: 4128
Own Kudos [?]: 9374 [2]
Given Kudos: 91
 Q51  V47
Send PM
Re: Three friends A, B and C decide to run around a circular track. They [#permalink]
2
Kudos
Expert Reply
sting8 wrote:
Is there any specific reason why A/C = 5/1 is rejected, and 5/3 is the OA
I feel both the options are viable.
Please help.

Also, in the real GMAT exam, is it possible to get questions which have multiple answers as per multiple cases, but OA is specific to only one case ?


You're right -- the question has two correct answers (one of which is not among the choices). That can't happen on the GMAT, at least when a question asks for an exact answer.

But there are several real GMAT questions that are phrased in this way:

If |x - 3| = 7, what could be the value of x?
A) -10
B) -7
C) -4
D) 4
E) 7


When the question asks what x "could" be, that phrasing indicates that the question may (and probably does) have more than one right answer, but you'll only find one of those answers among the choices. Here the absolute value equation has two solutions for x, 10 and -4, but only one of those is among the choices. But on the actual GMAT, the question above could never ask "What is the value of x?" because x does not have a unique value, so it would be mathematically incorrect to phrase the question that way.
RC & DI Moderator
Joined: 02 Aug 2009
Status:Math and DI Expert
Posts: 11443
Own Kudos [?]: 33564 [1]
Given Kudos: 317
Send PM
Re: Three friends A, B and C decide to run around a circular track. They [#permalink]
1
Kudos
Expert Reply
sting8 wrote:
Bunuel chetan2u IanStewart VeritasKarishma GMATinsight
Is there any specific reason why A/C = 5/1 is rejected, and 5/3 is the OA
I feel both the options are viable.
Please help.

Also, in the real GMAT exam, is it possible to get questions which have multiple answers as per multiple cases, but OA is specific to only one case ?

Thanks!



Both 5:3:1 and 5:4:3 are valid answers. The question is faulty in that it suggests there is only one solution: What is the ratio of the speeds of A, B and C?
So, if someone gets 5:3:1 through a certain method, it would surely hamper his speed, concentration and mind frame. Thai is not something GMAT would want, so you can safely assume that in GMAT, with such wordings, you should get only one answer.

Questions wherein there is a possibility of more than one answers the question would be phrased accordingly: Which COULD be a value and so on.

EDIT: It seems Ian too has answered the query in similar way while I was posting my thoughts. I agree with Ian completely on this issue.
Tutor
Joined: 16 Oct 2010
Posts: 14974
Own Kudos [?]: 66026 [2]
Given Kudos: 435
Location: Pune, India
Send PM
Re: Three friends A, B and C decide to run around a circular track. They [#permalink]
2
Kudos
Expert Reply
Bunuel wrote:
Three friends A, B and C decide to run around a circular track. They start at the same time, from the same point and run in the same direction. A is the quickest and when A finishes the first lap lap, C is as much behind B as B is behind A. When A completes 3 laps, C is at the exact same point on the circular track as B was when A finished the first lap. What could be the ratio of the speeds of A, B and C?

A. 6 : 5 : 3
B. 5 : 4 : 2
C. 4 : 3 : 2
D. 5 : 4 : 3
E. 3 : 2 : 1



Are You Up For the Challenge: 700 Level Questions


You can use the options to solve the question.

"when A finishes the first lap lap, C is as much behind B as B is behind A"
So the difference between the speed of A and B is the same as difference between the speed of B and C. Hence options (A) and (B) are out.

As per option (E), when A completes 3 laps, C would have completed 1 lap and would be at starting point too. But that is not possible. So (E) is out.

Now, check for option (C):
When A completes 1 lap, B completes 3/4 (three quarters of circle) and C completes 2/4 (Half of circle).
When A completes 3 laps, B completes 9/4 (quarter of circle) and C completes 6/4 (Half of circle)
C is not at the same position as B was.

Answer (D)

Let's check anyway:
When A completes 1 lap, B completes 4/5 and C completes 3/5 .
When A completes 3 laps, B completes 12/5 and C completes 9/5
Since 9/5 is (1 + 4/5), C is at the same position as B was.
Intern
Intern
Joined: 08 Oct 2020
Posts: 33
Own Kudos [?]: 15 [0]
Given Kudos: 27
Send PM
Three friends A, B and C decide to run around a circular track. They [#permalink]
firas92 wrote:
At the end of A's 3rd lap, the distance between A and C must be

Track length + Distance between A and B at the end of 1st lap

If the track length is 500m and the speed ratio is 5:4:3

A's first lap, A:B:C=500:400:300
A's second lap, A:B:C=1000:800:600
A's third lap, A:B:C=1500:1200:900

So the distance between A and C at the end of A's third lap is 1500-900=600=500+100 (track length + Distance between A and B at the end of A's first lap)

This perfectly matches our requirement.

Answer is (D)

Posted from my mobile device


firas92 @VeritasKarishma
GMATinsight
How did we deduce the equation

At the end of A's 3rd lap, the distance between A and C must be
Track length + Distance between A and B at the end of 1st lap


Why have we added Track length here, if I go based on algebraic equation it should
Assuming Track length as 100, At the end of 1st lap,
A = 100
B = 100-x
C = 100-2x
At 3rd Lap, A=300 , C=3(100-2x) = 300-6x
What am I missing here?
Again, By solving the same equation that says
When A completes 3 laps, C is at the exact same point on the circular track as B was when A finished the first lap.
300-6x = 100-x
x=40
I get the laps as
1st---- 100,60,20
2nd--- 200,120,40
3rd--- 300,240,60
and speed ratio as 5:4:1
Tutor
Joined: 16 Oct 2010
Posts: 14974
Own Kudos [?]: 66026 [1]
Given Kudos: 435
Location: Pune, India
Send PM
Re: Three friends A, B and C decide to run around a circular track. They [#permalink]
1
Kudos
Expert Reply
RajatGMAT777 wrote:
firas92 wrote:
At the end of A's 3rd lap, the distance between A and C must be

Track length + Distance between A and B at the end of 1st lap

If the track length is 500m and the speed ratio is 5:4:3

A's first lap, A:B:C=500:400:300
A's second lap, A:B:C=1000:800:600
A's third lap, A:B:C=1500:1200:900

So the distance between A and C at the end of A's third lap is 1500-900=600=500+100 (track length + Distance between A and B at the end of A's first lap)

This perfectly matches our requirement.

Answer is (D)

Posted from my mobile device


firas92 @VeritasKarishma
GMATinsight
How did we deduce the equation

At the end of A's 3rd lap, the distance between A and C must be
Track length + Distance between A and B at the end of 1st lap


Why have we added Track length here, if I go based on algebraic equation it should
Assuming Track length as 100, At the end of 1st lap,
A = 100
B = 100-x
C = 100-2x
At 3rd Lap, A=300 , C=3(100-2x) = 300-6x
What am I missing here?
Again, By solving the same equation that says
When A completes 3 laps, C is at the exact same point on the circular track as B was when A finished the first lap.
300-6x = 100-x
x=40
I get the laps as
1st---- 100,60,20
2nd--- 200,120,40
3rd--- 300,240,60
and speed ratio as 5:4:1


You are not wrong RajatGMAT777 (except for some calculation mistakes you have done in your last two steps)

I get the laps as
1st---- 100,60,20
2nd--- 200,120,40
3rd--- 300,240,60 (This should be 300, 180, 60)
and speed ratio as 5:4:1 (This should be 5:3:1)

That said, there are two possitibilites - C could have covered an entire track length and reached B's previous point or C may not have covered even one track length by the time A covers 3 laps.
So speeds of 5:4:3 as well as 5:3:1 are possible. The question mentions "could be the ratio" and that is why I would typically use the options to see which option "could" be the ratio. Now that I see other responses above, I guess the question started out by looking for an exact value and was later on updated.
User avatar
Non-Human User
Joined: 09 Sep 2013
Posts: 33648
Own Kudos [?]: 839 [0]
Given Kudos: 0
Send PM
Re: Three friends A, B and C decide to run around a circular track. They [#permalink]
Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.
Re: Three friends A, B and C decide to run around a circular track. They [#permalink]
Moderator:
Math Expert
93736 posts